mbly code to implement the y=(x1+x2)*(x3+x4) expression on 2-address machine, and then display the value of y on the screen. Assume that the values of the variables are known. Hence, do not worry about their values in your code.
The assembly instructions that are available in this machine are the following:
Load b, a Load the value of a to b
Add b, a Add the value of a to the value of b and pla
Answer:
SELECT vendor_number, vendor_name, CONCAT ('street', ' ' , 'city', ' ' , 'state', ' ' , 'zip code') as adress
FROM vendor_directory
ORDER BY vendor_name ASC;
Explanation:
* Suppose <u>vendor_directory</u> is the name of the table from which you extract the data with the SELECT sentence.
Answer:
The correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
Explanation:
The declaration given is:
int ar[3];
This means the array consists of three locations and is named as ar.
We know that the indexes are used to address the locations of an array and the index starts from 0 and goes upto to 1 less than the size of the array which means the indexes of array of 3 elements will start from 0 and end at 2.
Now in the given options we are using ndx variable to run the while loop.
So the code to assign zero to all elements of array will be
ndx = 0;
while(ndx<3)
{
ar[ndx] = 0;
ndx++;
}
Hence, the correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
Not really, because Java is an OOP programming language and JavaScript is an OOP scripting language.
Hope I helped!
~Mshcmindy
