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Norma-Jean [14]
3 years ago
9

What is the general form of the equation of a circle with center at (a, b) and radius of length m?

Mathematics
1 answer:
Serggg [28]3 years ago
7 0
In the problem, it says that the center of the circle is at point (a,b) and has a radius of length m. In this case, the standard form of the circle is represented by the equation (x-h) ^2 + (y-k)^2 = r^2. Upon substitution, (x-a) ^2 + (y-b)^2 = m^2.This is equal to x2 - 2ax + a2 + y2 -2by + b2  = m2. The equation that is similar here is A
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The standard diameter of a golf ball is 42. 67 mm. A golf ball factory does quality control on the balls it manufactures. Golf b
Fynjy0 [20]

The maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.

<h3>What is the range?</h3>

The range is the difference between the maximum and minimum.

Given to us

The standard diameter of a golf ball is 42.67 mm.

The discrepancy in diameter is more than 0.002 mm.

As it is given to us that the standard diameter of the golf ball is 42.67 mm while the discrepancy in diameter is more than 0.002 mm.

Maximum acceptable diameter = 42.67 mm + 0.002 mm = 42.672 mm

Minimum acceptable diameter = 42.67 mm - 0.002 mm = 42.668 mm

Hence, the maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.

Learn more about Range:

brainly.com/question/3507706

3 0
2 years ago
To watch the video
Anettt [7]

Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Using the formula:

v² - u² = 2 a h,

where

u = initial velocity of the ball = +120 ft/s

v = final velocity of the ball at the highest point = 0 ft/s

a = uniform acceleration acting on the ball = -32 ft/s²

h = height attained

Substituting the values we get;

0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.

7 0
3 years ago
Which of the following pairs of numbers has a GCF of 1? 30 and 70 24 and 44 12 and 30 16 and 21
stiv31 [10]
Must be 16 and 21 because we can see

30 and 70 has 10 as factor
24 and 44 has 2 as factor
12 and 30 has 2 as factor and all those factors are greater than one
5 0
3 years ago
Read 2 more answers
Every time I go to type a question it does this over and over where I can’t even type the question I’m looking for. Someone help
den301095 [7]

Answer: try checking your Wifi source and reopen the site if it's an app delete it then reinstall it another thing you can try is to restart your device or ask an IT in your family or one you know for help hope this works! :D

Step-by-step explanation:

7 0
3 years ago
2. What is the probability of spinning an A on the first spinner and an odd number
pychu [463]

Answer: <em>1/10</em>

Step-by-step explanation: These two events are independent, meaning the outcome of the first event doesn't affect the outcome of the second.

To find the probability of independent events, first, find the

probability of each event, then multiplies the probabilities.

The probability of spinning an A on the first spinner is 1/5

since there is 1 favorable outcome and 5 total outcomes.

The probability of spinning an odd number on the second spinner

is 3/6 which simplifies to 1/2 since there are 3 favorable outcomes,

spinning a 1, 3, or another 3 since these are odd numbers.

So now we have 1/5 × 1/2 and when multiplying fractions,

we multiply across the numerators and denominators to get 1/10.

So the probability of spinning an A, then an odd number is 1/10.

5 0
2 years ago
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