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NARA [144]
3 years ago
14

Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all

ergic to penicillin, Nathan has a 75% chance of having the same allergy. The doctor performed a skin test to see whether Nathan would react to it. The test is 98% accurate. If the test predicts that Nathan is NOT allergic to penicillin, what is the probability after the test that Nathan is NOT allergic to the drug?
Mathematics
2 answers:
ratelena [41]3 years ago
8 0
25% that he is not allergic to the drug
Morgarella [4.7K]3 years ago
3 0

<em>PLATO </em>Answer:  0.2450

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Order the numbers from least to greatest. 5 5/11, -5.5, 5.33 repeated, -5 4/5
nikdorinn [45]
Least to greatest: -5.5, -5, 5/11, 4/5, 5, 5.33 repeating
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3 years ago
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Trigonometry Dilemma
Vadim26 [7]

Answer:

17.1

Step-by-step explanation:

The missing side is x

  • tan 25° = \frac{opposite }{adjacent }
  • tan 25° = \frac{8}{x}                  

switch tan 25° and x

  • x = \frac{8}{tan 25}
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7 0
4 years ago
Please help!!!!!!!!!!
dexar [7]

Answer:

B: n+25=61

Step-by-step explanation:

if megan has 25 numbers and abby has n numbers and together they have 61, if you add 25 and n it should equal 61

6 0
4 years ago
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What is a 90% confidence interval for the true proportion of adult drivers who have often or sometimes talk on a cell phone when
Julli [10]

The question is incomplete. Here is the complete question.

USA Today reported that 36% of adult drivers admit that they often or sometimes talk on a cell phone when driving. This was based on a random sample of 1004 adult drivers.

a) What is a 90% confidence interval for the true proportion of adult drivers who have often or sometimes talk on a cell phone when driving?

b) What is a 95% confidence interval for the true proportion of adult drivers who have often or sometimes talk on a cell phone when driving?

c) What is a 99% confidence interval for the true proportion of adult drivers who have often or sometimes talk on a cell phone when driving?

d) What do you notice?

Answer and Step-by-step explanation: The way to calculate confidence interval for proportions is by using the following formula:

z(\sqrt{\frac{p(1-p)}{n} } )

where

p is the sample population proportion

n is the number of individuals in the sample

z is z-score associated of the % of confidence

a) A 90% confidence has a z-score of z = 1.645

Calculating:

Interval = 1.645(\sqrt{\frac{0.36(1-0.36)}{1004} } )

Interval = 1.645(\sqrt{0.00023} )

Interval = 1.645(0.01515)

Interval = 0.025

A 90% Confidence interval for true population is between 0.335 and 0.385.

b) A 95% confidence has a z-score of z = 1.96

Since the sample parameter didn't change, the interval will be:

Interval = 1.96(0.01515)

Interval = 0.03

For a 95% confidence, interval is between 0.33 and 0.39.

c) A 99% confidence has a z-score of z = 2.58

Interval = 2.58(0.01515)

Interval = 0.39

For a 99% confidence, interval is between -0.03 and 0.75

d) Confidence interval tells you how certain your results from polling or survey would represent the real population's behaviour. In the experiment above, as the percentage of certainty grows, closer the real population proportion actually is for adult drivers who often or sometimes talk on a cell phone when driving.

8 0
3 years ago
What is the modal group
Maru [420]

Answer:

Im pretty sure it means the highest number in a group of numbers

Step-by-step explanation:

7 0
3 years ago
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