2 Answers:
Choice C) It will use a closed circle
Choice D) The ray will move to the left
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Explanation:
The inequality 
means that x = -8 or x < -8. Since we're including -8 itself, which is the endpoint, we'll use a closed circle. In contrast, an open circle would be used if the inequality was 
to exclude the endpoint -8.
The ray is to the left because we're visually describing all values smaller than -8. Such example values are -10 and -22 as these values are to the left of -8 on the number line.
In short, the graph consists of a closed circle at the endpoint -8 and the arrow is to the left. We can say the shading is to the left.
502 and 63 have no common factors:
Factors of 63: 1, 3, 7, 9, 21, 63
Factors of 502: 1, 2, 251, 502
Therefore the simplest form of 502/63 is 502/63
Answer:
the y-intercept is -1, or (0, -1)
Step-by-step explanation:
Identify the coordinates of the point where the line crosses the y-axis. They are (0, -1), and so the y-intercept is -1, or (0, -1).
The answer is: 
The correct option is: (D)
<h3>What are Complex numbers?</h3>
A complex number is the sum of a real number and an imaginary number. A complex number is of the form a + ib and is usually represented by z. Here both a and b are real numbers. The value 'a' is called the real part which is denoted by Re(z), and 'b' is called the imaginary part Im(z).
Since we have given : 
and 
The difference of z1 - z2 would be:
So,
Hence,
Learn more about Complex Number here:
brainly.com/question/14028757
#SPJ1
The answer is: " x = 0, 1 " .
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Explanation:
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Given:
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" √(x + 1) <span>− 1 = x " ; Solve for "x" ;
First, let us assume that "x </span>≥ -1 "
<span>
Add "1" to EACH SIDE of the equation:
</span>→ √(x + 1) − 1 + 1 = x + 1 ;
to get:
→ √(x + 1) = x + 1 .
Now, "square" EACH side of the equation:
→ [√(x + 1) ]² = (x + 1 )² ;
to get:
x + 1 = (x + 1)²
↔ (x + 1)² = (x + 1) .
Expand the "left-hand side" of the equation:
→ (x + 1)² = (x + 1)(x +1) ;
Note: (a+b)(c+d) = ac +ad + bc + bd ;
As such: (x + 1)(x + 1) = (x*x) + (x*1) +(1(x) + (1*1) ;
= x² + 1x + 1x + 1 ;
= x² + 2x + 1 ;
Now, substitute this "expanded" value, and bring down the "right-hand side" of the equation; and rewrite the equation:
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" (x + 1)² = (x + 1)(x +1) " ;
→ Rewrite as: " x² + 2x + 1 = x + 1 " ;
Subtract "x" ; and subtract "1" ; from EACH SIDE of the equation:
→ x² + 2x + 1 - x - 1 = x + 1 - x - 1 ;
to get: → x² <span>− x = 0
Factor out an "x" on the "left-hand side" of the equation:
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</span>x² − x = x(x − 1) ;
→ x (x − 1) = 0 ;
We have: "x" and "(x − 1)" ; when either of these two multiplicands are equal to zero, then the "right-hand side of the equation equals "zero" .
So, one value of "x" is "0" .
The other value for "x" ;
→ x − 1 = 0 ;
Add "1" to each side of the equation:
→ x − 1 + 1 = 0 + 1 ;
→ x = 1 ;
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So, the answers:
" x = 0, 1 " .
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