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kicyunya [14]
3 years ago
11

The elevator is a business center has a weight limit of 1800 pounds assume the average person weighs 160 pounds and has 3 pounds

of items with them what is the greatest number of people that can ride the elevator at one time
Mathematics
1 answer:
marta [7]3 years ago
3 0
11 people. 160+3 = 163. 1800/163 = 11.0429. Since you can not have a part of a person you have to round down to 11
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alexira [117]

Answer: -1

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Lucia estimates the attendance at the middle school concert to be 267. The actual attendance is 304.
USPshnik [31]

Answer:

12%

Step-by-step explanation:

Divide 267 by 304

Lucia got 88% correct

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2 years ago
Solve for n.<br> 1–3n=<br> –<br> 9+n+2
iris [78.8K]

Answer:

Step-by-step explanation:

1-3n=-9+n+2 ---> -3n-n=-1+-9+2 --> -4n=-8 ---> n=2

3 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
Help on 3. And 4. Thank you!
chubhunter [2.5K]

Answer:

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

Up to and after 45 minutes, the barrel is empty of water.

Step-by-step explanation:

#2.)  

minutes:      5, 10, 15, 20

water(gal):  16, 14, 12, 10

Find slope:    slope m = (14 - 16)/(10 - 5) = -2/5

y - 10 = (-2/5)*(x - 20)

y - 10 = (-2/5)* x  + 8

y = (-2/5)*x + 18

rate of change slope means that for every minute  2/5 gallons of water is lost

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

4 0
3 years ago
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