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xxMikexx [17]
4 years ago
14

What is the factored form of 4a^3b^5 − 16a^5b^2 + 12a^2b^3

Mathematics
2 answers:
Gre4nikov [31]4 years ago
8 0
4a^3b^5 - 16a^5b^2 + 12a^2b^3 =
4a^2b^2 (ab^3 - 4a^3 + 3b) <==
Crank4 years ago
7 0
Here's the answer if I'm not wrong

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A.22<br> B.68<br> C.118<br> D.119
rjkz [21]
See the attached picture:

4 0
3 years ago
Image WXYZ has the following vertices - W(3, -4), X(1, 0), Y(5, -1), Z(4, -4). Image WXYZ is rotated 180 degrees about the origi
olya-2409 [2.1K]

Answer:

Step-by-step explanation:

c

8 0
3 years ago
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How do you find the percent of increase from 12 to 18?
olga nikolaevna [1]
Let's get the data out of the problem:

Nv = 18

Ov = 12

Now, we can apply in this equation that relates the new and the old values:

i = Nv / Ov

i = 18 / 12

i = 1.5

Now, we just consider what has passed from 1, and this is 0.5, converting to percentage it is:

p = 0.5 . 100

p = 50%

The increase was 50%.

Hope it helps.
4 0
3 years ago
Find the period. Principal = 9300 =9300equals, 9300 rupees Annual rate of interest = 13 % =13%equals, 13, percent Total amount =
tekilochka [14]

Answer:

7 years

Step-by-step explanation:

Given:

Principal P = 9300

Interest rate r = 13% = 0.13

Final amount F = 17,763

Since the problem does not state that it is a compounded interest, we will assume this is a simple interest case.

The formula for simple interest is;

Interest I = Prt .....1

t = period

Final amount F = P + I

I = F-P

Substituting into equation 1;

(F-P) = Prt

t = (F-P)/Pr

Substituting the given values;

t = (17,763 - 9300)/(9300×0.13)

t = 7 years

Period = 7 years

5 0
4 years ago
CAN SOMEONE PLEASE HELP ME!!!!
padilas [110]

Answer:

The third answer aka C

Step-by-step explanation:

6 0
3 years ago
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