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WITCHER [35]
3 years ago
8

16 is 8 times as many as 2

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0
Are you asking whether this is true?

let's check how much is "8 times as many as 2":

we do this by multiplication: 8*2.

8*2=16 (in other words: 8+8=16)

so, yes, the sentence is correct.
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PLEASE PLEASE PLEASE HELP!!
Marta_Voda [28]
Okay I'll try to show it step by step

Step 1. So first you need to recognise that the diagram is a right angled triangle, with the right angle being at the bottom. This means we can do Pythagoras' Theorem.

Step 2. Now that you know you can use Pythagoras' Theorem, you can apply it. If you don't know, the theorem is a² + b² = c², with, in this case, a being 5 and b being 8. This means we can do 5² + 8² = 25 + 64 = 89.

Step 3. From the previous step, we now know that the length of the side including x is √89, and because we know that part of this side is 3, if we subtract 3 from √89 we get the value of x, so: √89 - 3 = 9.434 - 3 = 6.434, which is your answer.

I hope this helps!
5 0
3 years ago
What's measure E & D?
Kipish [7]
You'll have to show work guaranteed.......so i'll tell you that you need to inverse 

3 0
4 years ago
The location of the incenter<br> of AABC is:<br><br> A. Point D<br> B. Point E<br> C. Point F
Leviafan [203]

Answer:

B

Step-by-step explanation:

( point E)

6 0
2 years ago
The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6.
Wittaler [7]

Answer:

a) There is a 10.75% probability of observing less than 60 hits in an hour.

b) The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) There is a 24% probability of observing between 80 and 90 hits an hour

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem, we have that

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6, so \mu = 75, \sigma = 8.6.

a) What’s the probability of observing less than 60 hits in an hour? Use the normal approximation

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 75}{8.6}

Z = -1.74

Z = -1.74 has a pvalue of 0.1075. This means that there is a 10.75% probability of observing less than 60 hits in an hour.

b) What’s the 99th percentile of the distribution of the number of hits?

What is the value of X when Z has a pvalue of 0.99.

Z = 2.35 has a pvalue of 0.99

So

Z = \frac{X - \mu}{\sigma}

2.35 = \frac{X - 75}{8.6}

X - 75 = 20.21

X = 95.21

The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) What’s the probability of observing between 80 and 90 hits an hour?

This is the pvalue of the zscore of X = 90 subtracted by the pvalue of the zscore of X = 80.

For X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 75}{8.6}

Z = 1.74

Z = 1.74 has a pvalue of 0.95907

For X = 80

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 75}{8.6}

Z = 0.58

Z = 0.58 has a pvalue of 0.71904

So

There is a 0.95907 - 0.71904 = 0.24003 = 24% probability of observing between 80 and 90 hits an hour

6 0
3 years ago
Penny bought a juice squeezer for $10. She can make a bottle of orange juice for a cost of $0.75, and she sells her orange juice
azamat
Is there more to this question?

7 0
3 years ago
Read 2 more answers
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