3 years ago

Apply the distributive property to create an equivalent expression. (6m – 7). 4=

Mathematics

2 answers:

tangare [24]3 years ago

7 0

Answer:

24m-28

Step-by-step explanation:

24m-28

Savatey [412]3 years ago

6 0

Answer: 24m-28

Step-by-step explanation:

According to the distributive property ,

$a(b+c) = ab+ac$

$(b+c)a = ba+ca$ , where a, b and c are any arbitrary expressions.

Given expression : $(6m-7)\cdot4$

By using distributive property , we have

$(6m - 7)\cdot 4= (6m)(4)-(7)(4)\\\\= (6)(4)(m)-28 \ \ \ [\text{By associative property}]\\\\=24m-28$

Hence, the required equivalent expression is 24m-28.

You might be interested in

Write a reciprocal function with asymptotes x=4 and y=-9.

gayaneshka [121]

Attached the solution and work.

5 0

3 years ago

Isabel began training for a marathon by running 63 miles during her first week. Each week, she increased the distance she ran by

Ulleksa [173]

Answer:

10% of 63 is 6.3 so 63+6.3=69.3

Step-by-step explanation:

7 0

3 years ago

Graph the given equation: y=2x+1

lions [1.4K]

So your slope is 2 and your Y-intercept is 1.

To graph it, start at 0 and go up to number 2.

8 0

3 years ago

I need to solve and show work for 3x over4 divided by 5-1 over 8

likoan [24]

3or4vxe
4

Is the answer

5 0

3 years ago

Read 2 more answers

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago