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LekaFEV [45]
3 years ago
12

Simplify 15x^2-18/6 A. 15x+3 B. X+3 C. 5x^2-18/2 D. 5x^2-6/2

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

D. 5x^2-6/2

Step-by-step explanation:

5x^2-18/6 , 18/6 is 6/2

5x^2-6/2 ,

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The houck family's train traveled 552 miles in 6 hours. The Roberts family traveled at 744 miles in 8 hours which family is trav
rusak2 [61]

Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.

Step-by-step explanation: Speed of Houck family's train = 552m/6hrs

speed of Robert family's train = 744m/8hrs.

Therefore considering Houck speed,

552miles = 6hours

1mile = (6 x 60)/552

= 360/552

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

For Robert

744miles = 8hours

1mile = ( 8 x 60 )/744

= (480/744)minutes

= 0.645

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

Conclusion: Both families were travelling at the same speed/rate.

To get that minutes in hour, just divide by 60 to get concert to hours.

6 0
3 years ago
Outline the process for Inscribing an equilateral triangle in a circle. Perform the construction in GeoGebra, and take a
mezya [45]

Answer:

I don't use Geogebra, but the following procedure should work.

Step-by-step explanation:

Construct a circle A with point B on the circumference.

  1. Use the POINT and SEGMENT TOOLS to create a circle with centre B and radius BA.
  2. Use the POINT tool to mark points D and E where the circles intersect.
  3. Use the SEGMENT tool to draw segments from C to D, C to E, and D to E.

You have just created equilateral ∆CDE inscribed in circle A.

 

5 0
3 years ago
4 to 7 equals 21 to what ​
Margaret [11]
Can you show the whole question
8 0
3 years ago
Read 2 more answers
PLEASE NO LINKS Thank you :)
alexgriva [62]

Answer:

hon you never asked a question or added an image. id be happy to try and help if you do!

6 0
2 years ago
Read 2 more answers
How to solve the equations
satela [25.4K]
You would do parentheses first and that answer you will x 7
6 0
3 years ago
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