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hichkok12 [17]
3 years ago
7

If the work done to stretch an ideal spring by 4.0 cm is 6.0J, what is the spring constant (force constant) of this spring?

Physics
2 answers:
cluponka [151]3 years ago
8 0
As AL2006 correctly pointed out the formula is 1/2 kx^2.  I was thinking of force and work is the integral of force over the distance applied.  So now
W= \frac{1}{2}k x^{2}
and
\frac{2*6.0}{0.04^{2} } = k =7500 \frac{J}{m^{2}}
ikadub [295]3 years ago
5 0

Answer:

Spring constant or the force constant, k = 7500 N/m.

Explanation:

Given that,

Energy stored in the spring, E = 6 J

Stretching in the spring, x = 4 cm = 0.04 m

To find,

The spring constant (force constant) of this spring.

Solution,

We know that the work done by the spring when it is stretched is given by :

W=\dfrac{1}{2}kx^2

k is the spring constant

k=\dfrac{2W}{x^2}

k=\dfrac{2\times 6}{(0.04)^2}

k = 7500 N/m

So, the spring constant (force constant) of this spring is 7500 N/m.

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Mnenie [13.5K]

Answer:

The part that completes the nuclear equation is:

           ^{221}_{87}Fr

Explanation:

<h2>A) Preliminar explanation</h2>

The <em>nuclear equation</em> represents a nuclear reaction: the change of the nucleus of an atom.

The given equation represents an actinium atom releasing an alpha particle.

This is the meaning of each part of the equation:

  • Ac is the chemical symbol of actinium
  • The superscript to the left of the chemical symbol is the mass number of the atom (number of protons plus number of neutrons). The mass number is 225.
  • The subscript to the left of the chemical symbol is the atomic number of the atom (number of protons). The atomic number is 89.

  • ^4_2He is the symbol of the alpha particle. It is an atom of helium
  • The mass number is 4
  • The atomic number is 2

<h2>B) Solution</h2>

To <em>complete the nuclear equation </em>you must do two balances: mass number balance and atomic number balance.

<u>i) Mass number balance</u>

  • 225 = A + 4 ⇒ A = 225 - 4 = 221

<u>ii) Atomic number balance</u>

  • 89 = Z + 2 ⇒ Z = 89 - 2 = 87

Therefore, the mass number of the unknown atom is 221, and the atomic number is 87.

From a periodic table, the element with atomic number 87 is francium, Fr.

Now, you have the chemical symbol, the atomic number, and the mass number of the unknown atom, which lets you to write the atom that completes the <em>nuclear equation</em>.

           ^{221}_{87}Fr

7 0
3 years ago
A wheel turns through 5.5 revolutions while being accelerated from rest at 20rpm/s.(a) What is the final angular speed ? (b) How
alina1380 [7]

Answer:

(a) The final angular speed is 12.05 rad/s

(b) The time taken to turn 5.5 revolutions is 5.74 s

Explanation:

Given;

number of revolutions, θ = 5.5 revolutions

acceleration of the wheel, α = 20 rpm/s

number of revolutions in radian is given as;

θ = 5.5 x 2π = 34.562 rad

angular acceleration in rad/s² is given as;

\alpha = \frac{20 \ rev}{min} *\frac{1}{s} *(\frac{2\pi \ rad}{1 \ rev } *\frac{1 \ min}{60 \ s}) \\\\\alpha = 2.1 \ rad/s^2

(a)

The final angular speed is given as;

\omega _f^2 = \omega_i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 +  2\alpha \theta\\\\\omega _f^2 =   2\alpha \theta\\\\\omega _f = \sqrt{2\alpha \theta}\\\\ \omega _f  = \sqrt{2(2.1) (34.562)}\\\\ \omega _f = 12.05 \ rad/s

(b) the time taken to turn 5.5 revolutions is given as

\omega _f = \omega _i + \alpha t\\\\12.05 = 0 + 2.1t\\\\t = \frac{12.05}{2.1} \\\\t = 5.74 \ s

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