A stunt man is being pulled, at a constant velocity, along a rough road by a cable attached to a truck. The cable is parallel to
the ground. The mass of the stunt man is 109 kg, and the coefficient of kinetic friction between the road and the stunt man is 0.870. Find the tension in the cable.
2 answers:
Answer:
the tension in the cable= 929.33N
Explanation:
the tension in the cable is equivalent to the frictional force experienced between the road and the stunt man
coefficient of friction= μ=
μ=0.870
N= Normal force =m × g
m= 109kg
g= acceleration due to gravity =9.8m/s²
= μ × N
= μ × m × g
= 0.870 × 109 × 9.8
=929.33N
The tension in the cable is 929.33N
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Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
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