A stunt man is being pulled, at a constant velocity, along a rough road by a cable attached to a truck. The cable is parallel to
the ground. The mass of the stunt man is 109 kg, and the coefficient of kinetic friction between the road and the stunt man is 0.870. Find the tension in the cable.
2 answers:
Answer:
the tension in the cable= 929.33N
Explanation:
the tension in the cable is equivalent to the frictional force experienced between the road and the stunt man
coefficient of friction= μ=
μ=0.870
N= Normal force =m × g
m= 109kg
g= acceleration due to gravity =9.8m/s²
= μ × N
= μ × m × g
= 0.870 × 109 × 9.8
=929.33N
The tension in the cable is 929.33N
You might be interested in
Answer:
The maximum amount of work is
Explanation:
From the question we are told that
The temperature of the environment is
The volume of container A is
Initially the number of moles is
The volume of container B is
At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as
Now from the Ideal gas law
So substituting for in the equation above
Where R is the gas constant with a values of
Substituting values we have that