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3 years ago

How long will it take to travel 200 km traveling 10 m/s ?

1 answer:

5 0

<span>Convert 200 km to meters which equals 200000 meters. Then take 10m/s*200000meters which equals 2000000 seconds.
</span>

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Which automobile is faster a chevrolet or a ford? Also explain pls

antiseptic1488 [7]

Answer:

depends on what type of car it is

Explanation:

6 0

2 years ago

Read 2 more answers

If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?

Zarrin [17]

Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

$W=F\times x$

$W=mg\times x$

Where, x = distance

mg = weight

Put the value into the formula

$W=40\times2$

$W= 80\ Nm$

$W=80\ J$

Hence, The work done on the box is 80 J.

5 0

3 years ago

2. A pair of narrow, parallel slits sep by 0.25 mm is illuminated by 546 nm green light. The interference pattern is observed on

Agata [3.3K]

Answer:

for the first interference m = 1 y = 2,839 10-3 m

for the second interference m = 2 y = 5,678 10-3 m

Explanation:

The double slit interference phenomenon, for constructive interference is described by the expression

d sin θ = m λ

where d is the separation between the slits, λ the wavelength and m an integer that corresponds to the interference we see.

In these experiments in general the observation screen is L >> d, let's use trigonometry to find the angles

tan θ = y / L

with the angle it is small,

tan θ = sin θ / cos θ = sin θ

we substitute

sin θ = y / L

d y / L = m λ

the distance between the central maximum and an interference line is

y = m λ L / d

let's reduce the magnitudes to the SI system

λ = 546 nm = 546 10⁻⁹ m

d = 0.25 mm = 0.25 10⁻³ m

let's substitute the values

y = m 546 10⁻⁹ 1.3 / 0.25 10⁻³

y = m 2,839 10⁻³

the explicit value for a line depends on the value of the integer m, for example

for the first interference m = 1

the distance from the central maximum to the first line is y = 2,839 10-3 m

for the second interference m = 2

the distance from the central maximum to the second line is y = 5,678 10-3 m

3 0

3 years ago

The location movement and intensity of precipitation can be found by using?

vaieri [72.5K]

<span>Answer: Doppler radar
Doppler radar or weather radar is used to locate precipitation,</span> forecast future intensity, calculate or detecting its motion and estimates precipitation whether it is a rain, snow, hail or storm. They are also helpful in determining the structure of storms and its potential to cause severe weather.

Moreover, if a portion of the atmosphere becomes saturated with water vapor, it will condense and precipitate allowing Doppler radar to analyze and observe precipitation.

4 0

2 years ago

ASK YOUR TEACHER A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 51.5-gram mass is attach

Simora [160]

Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W' the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

6 0

3 years ago