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DochEvi [55]
3 years ago
11

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)

Physics
2 answers:
Artyom0805 [142]3 years ago
7 0
A) Speed..............
Varvara68 [4.7K]3 years ago
7 0

Answer:

Ok

Explanation:

Speed

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A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally holding a stopwatch, n
valkas [14]

Answer

given,

height of window = 4 m

time taken to travel = 1 s

acceleration due to gravity = 9.8 m/s²

s = ut + \dfrac{1}{2}at^2

u = \dfrac{s - \dfrac{1}{2}at^2}{t}

u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}

u = -0.905 m/s

initial velocity of ledge v = 0

now,

v² = u² + 2 a s

(-0.905)² = 0 + 2 × 9.8 ×s

s = 0.042 m

6 0
3 years ago
If the amplitude of a simple harmonic oscillator is doubled, by what factor does the total energy increase?
dybincka [34]

Answer:

c)by a factor of four

Explanation:

The total energy of a simple harmonic oscillator is given by

E=\frac{1}{2}kA^2

where

k is the spring constant of the oscillator

A is the amplitude of the motion

In this problem, the amplitude of the oscillator is doubled, so

A' = 2A

Therefore, the new total energy is

E'=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E

So, the total energy increases by a factor 4.

6 0
3 years ago
Make the following conversion.
anastassius [24]
The answer is 0.00230 cm
4 0
3 years ago
Read 2 more answers
Sulfur oxides (SO2) are responsible for
tigry1 [53]
B green house gases is the correct problem
5 0
3 years ago
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A solid block, with a mass of 0.15kg, on a frictionless surface is pushed directly onto a horizontal spring, with a spring const
iren [92.7K]

Answer:

16.1 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by

U=\frac{1}{2}kx^2

where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to

K=\frac{1}{2}mv^2

where m = 0.15 kg is the mass of the block and v is its speed.

Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:

\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(316 N/m)(0.35 m)^2}{0.15 kg}}=16.1 m/s

4 0
4 years ago
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