Answer:
I) Option 2)
II) Minimum 35 passengers must be carried in the flight to make a profit.
Step-by-step explanation:
We are given the following in the question:
I) Number of seats in plane = 295
Estimated cost = $3,845
Cost per passenger= $110 per hour of flight
Let x be the number of passenger travelling by flight.
Total cost =
Then, we can design the profit function as:
The domain is the collection \of all the values of x for which the function is defined.
Thus, the domain of the profit function will be
Option 2)
II) least number of passengers it must carry to make a profit
Thus, minimum 35 passengers must be carried in the flight to make a profit.
Answer: Negative
Step-by-step explanation:
use the slope formula:
plug in values of two points...
I will use (-4, 2) and (0,0)
⇒
⇒
Therefore, the slope is
⇒ , which is negative
60 hundreds if it says hundreds then it would still be that
A^2+b^2=c^2
8^2+6^2=c^2
64+36=c^2
100=c^2
C=10
Answer:
- The probability that the locker code begins with a prime number is 40%.
- The probability that the last digit of the locker code is an odd number is 40%
Step-by-step explanation:
- Prime numbers are the numbers that only divide with 1 or itself. So in this case it is 5 and 7.
The possible combinations are
1*4*3 (with 5) + 1*4*3(with 7) = 24
Total combinations are 5*4*3=60
(24/60)*100 = 40 %
2. Odd numbers are those which don't divide with 2. So in this case it is 6 and 8.
The possible combinations are
1*4*3 (with 6) + 1*4*3(with 8) = 24
Total combinations are 5*4*3=60
(24/60)*100 = 40 %