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3 years ago

Which contribution added to Rutherford's discovery of a positive nucleus?

Physics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

Its B. because he did discovered that electrons are scatterd in a atom

OverLord2011 [107]3 years ago

7 0

B) Electrons are scattered in an atom.

is the answer

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A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the

Genrish500 [490]

Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

$a_c =w^2r = \frac{v^2}{r}$

in this case we know the speed of the runner

$v =8.00\ m/s$

The radius "r" will be the distance from the runner to the center of the track

$r = 28.2\ m$

$a_c = \frac{8^2}{28.2}\ m/s^2$

$a_c = 2.27\ m/s^2$

The answer is the last option

3 0

3 years ago

Is an example of a physical process that a physical geographer would study.

diamong [38]

D. The environment
Is the right answer

8 0

3 years ago

If the velocity of a runner changes from -2 m/s to -4 m/s over a period of time, the

Mnenie [13.5K]

Answer:

It will be A. So since its 2 times more the kinetic energy. But then you have to square it 2^2 = 4

3 0

3 years ago

How long does it take electrons to get from

OlgaM077 [116]

We need to find the time it takes an electron to move in the given circuit.

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

I = Current = 134 A

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

A = Area = $38.9\ \text{mm}^2$

L = Length = 92.2 cm

$\rho$ = Density of copper = $8960\ \text{kg/m}^3$

M = Molar mass of copper = 63.5 g/mol

$n_v$ = Number of valence electrons of copper = 1

e = Charge of electron = $1.6\times 10^{-19}\ \text{C}$

Number of charge carriers per unit volume is given by

$n=\dfrac{\rho N_An_v}{M}\\\Rightarrow n=\dfrac{8960\times 6.022\times 10^{23}\times 1}{63.5\times 10^{-3}}\\\Rightarrow n=8.497\times 10^{28}\ \text{m}^{-3}$

Time taken is given by

$t=\dfrac{LAne}{I}\\\Rightarrow t=\dfrac{92.2\times 10^{-2}\times 38.9\times 10^{-6}\times 8.497\times 10^{28}\times 1.6\times 10^{-19}}{134}=3638.83\ \text{s}\\\Rightarrow t=\dfrac{3638.83}{60}=60.65\ \text{minutes}$

The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.

Learn more:

brainly.com/question/1426683

brainly.com/question/170663

8 0

2 years ago

Perception Distance + Reaction Distance + Braking Distance = _____________.

scZoUnD [109]

Answer:

option B) is correct

Explanation:

perception distance is the distance traveled by the vehicle when the driver perceive the hazard situation.

reaction distance is the distance traveled by the vehicle after seeing the hazard situation and reacting to it.

Braking Distance is the distance traveled by the vehicle after applying the brake.

so, the sum of Perception Distance + Reaction Distance + Braking Distance is called the total stopping distance

hence option B) is correct .

4 0

3 years ago