The value of t for which the particle is at rest is : t = 2
<u>Given data:</u>
X = t³ - 3t²
Y = 2t³ - 3t² - 12t
<h3>Determine the values of t for which the particle is at rest </h3>
<u>First step : Determine the first derivative of eac equations</u>
dx = 3t² - 6t
dy = 6t² - 6t - 12
<u>Next step : </u><u>determine</u><u> the value of slope ( dy/dx ) = o </u>
dy / dx = ( 6 (t² - t - 2) ) / ( 3t ( t - 2) )
Therefore
dy / dx = ( 2 ( t + 1 ) (t - 2) ) / ( t ( t -2) )
= 0
Therefore at ; t = -1 and 2 the particle is at rest
Hence we can conclude that Neglecting the negative value the particle will be at rest when t = 2
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<u>Attached below is the complete question</u>
<em>The position of a particle moving in the xy-plane is given by the parametric equations x = t3 - 3t2 and y = 2t3 - 3t2 - 12t. For what values of t is the particle at rest?</em>
The answer is True the mass is the matter of the object while the weight is the gravitational force on the object
Answer:
Explanation:
area of the coil A = .08 x .08 = 64 x 10⁻⁴ m ²
flux through the coil Φ = area of coil x no of turns x magnetic field
= 64 x 10⁻⁴ x 50 x B where B is magnetic field
emf induced = dΦ / dt = ( 64 x 10⁻⁴ x 50 x B - 0 ) / .2
= 1.6 B
current induced = emf induced / resistance
12 x 10⁻³ = 1.6 B / 15
B = 112.5 x 10⁻³ T .
Answer:
B = Bo / 2
Explanation:
Magnesium and electric fields are related in an electromagnetic wave
E / B = c
If the electric field is halved the magnetic field must also be halved to meet the written equation
B = Bo / 2
Saying no and not throwing fits and manners.
