4 years ago

What is the average of 143, 98, and 128

Mathematics

1 answer:

asambeis [7]4 years ago

8 0

$Average\ A=\frac{S}{N}\\\\A=\frac{143+98+128}{3}=\frac{369}{3}=123\\\\Average\ of\ these\ numbers\ is\ 123.$

You might be interested in

What is the product? 6(x*2-1)(6x-1/6(x+1))

Yanka [14]

6(x^2-1)(6x-1/6(x+1))

On factoring (x^2-1)=(x+1)(x-1)

= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,

= 6(x-1)(6x-1)/6

Cancelling 6 we get,
= (x-1)(6x-1)

4 0

3 years ago

15 points f (x) = 1/x+5 -1. Find the inverse of (x) and its domain.

erastovalidia [21]

Answer:

Step-by-step explanation:

$f(x)=\frac{1}{x+5} -1\\let~f(x)=y\\y=\frac{1}{x+5} -1\\flip~x~and~y\\x=\frac{1}{y+5} -1\\x+1=\frac{1}{y+5} \\y+5=\frac{1}{x+1} \\y=\frac{1}{x+1} -5\\f^{-1}(x)=\frac{1}{x+1} -5\\x+1\neq 0\\x\neq -1$