Area is Length x width.
Area = 4x * 5
Area = 20x
Replace A in the inequality:
Now you have 100 <= 20x <= 1,000
Now solve for x by dividing all 3 by 20:
5 <= x <=50
Check to see if they are viable:
4(5) x 5 = 20 x 5 = 100
4(50) x 5 = 200 x 5 = 1,000
Since the lowest number equals 100 and the largest number equals 1,000 all values of x would be viable. The answer is YES.
Answer:
y = -x + 2
Step-by-step explanation:
— 5х – 4у = -8
-4y = 4x - 8
4y = -4x + 8
y = -x + 2
Let the marks of the students in class 1 be
the average of these 12 marks is 90, so
which means
similarly, let
be the marks of the students in the second class,
so
which means
The 32 students averaged:
If "4/2/7" is all we have to work with, then PEMDAS rules will save the day. Do the division from left to right.
4/2 becomes 2. Then we have 2/7, a proper fraction. I don't see where an improper fraction would come from in this case.
