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3 years ago

Maria wrote the equation of a line that has a slope of Four-thirds and passes through point (3, 5). Which statement is true?

2 answers:

5 1

MATH NIMBERS BAL BLAH BLAH NUMBERS MATH BLAH NLAH MATH. UNBRR POOJTS BLAH BLAH MAKE THE POINTS HIGHER PLEASE THEN I ANSWER BLAH BAH BLAH

thisusernameisalreadytaken

2 years ago

...wooooow so helpful... although it does seem like that....

Maksim231197 [3]3 years ago

5 0

Statement 1 is correct

as 5 = 4/3(3) + 1

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C(1)=−20<br> c(n)=c(n−1)+10<br><br> Find the second term in the sequence. <br>

svet-max [94.6K]

Answer:

c(2) = -10

Step-by-step explanation:

The first equation says that the first term of the sequence is -20.

The second equation is saying that to find any term of the sequence, add 10 to the previous term.

c(2) = c(2-1) + 10

c(2) = c(1) + 10

c(2) = -20 + 10 = -10

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2 years ago

I need help like really bad

serg [7]

Answer:

Step-by-step explanation:

14/15 is less than 7/5

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3 years ago

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Which of the following options is the inverse of an exponential function?

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Logarithmic function

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3 years ago

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How would i reduce 10/100 with the work problem to go with it

AlekseyPX

Answer:

1/10

Step-by-step explanation:

you can simply show the cancellation of the zeros

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3 years ago

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Find the exact value of cos(7\pi /12)

Naya [18.7K]

7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.

Recall that

$\cos^2x=\dfrac{1+\cos(2x)}2$

which tells us

$\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1+\cos\left(\frac{7\pi}6\right)}2}$

Now,

$\cos\left(\dfrac{7\pi}6\right)=-\cos\left(\dfrac\pi6\right)=-\dfrac{\sqrt3}2$

and so

$\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1-\frac{\sqrt3}2}2}=\boxed{-\dfrac{\sqrt{2-\sqrt3}}2}$

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3 years ago