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Elanso [62]
3 years ago
6

Sodium hydroxide is a substance that causes severe burns. It is used in many educational laboratory activities but, because of i

ts hazardous nature, care must be taken to ensure its safe use in the lab Select the following items that are true regarding the nature of sodium hydroxide, and the safety precautions that should be used when handling it in the laboratory. Select all that apply.
a. If sodium hydroxide is spilled on skin or clothing, the contaminated clothing should be removed immediately and the affected area should be drenched with plenty of water. Medical attention should be sought if a large area is affected, or if blistering occurs.
b. Sodium hydroxide solutions are particularly dangerous to the eyes
c. Sodium hydroxide solutions with high concentration can cause severe burns
d. If sodium hydroxide is introduced to the eyes, flush the affected eye continuously with water for at least 15 minutes. Get medical attention immediately.
e. Eye protection should be worn at all times when handling any form of sodium hydroxide
Chemistry
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

All the alternatives are TRUE

a. If sodium hydroxide is spilled on skin or clothing, the contaminated clothing should be removed immediately and the affected area should be drenched with plenty of water. Medical attention should be sought if a large area is affected, or if blistering occurs.

b. Sodium hydroxide solutions are particularly dangerous to the eyes

c. Sodium hydroxide solutions with high concentration can cause severe burns

d. If sodium hydroxide is introduced to the eyes, flush the affected eye continuously with water for at least 15 minutes. Get medical attention immediately.

e. Eye protection should be worn at all times when handling any form of sodium hydroxide

Explanation:

Sodium hydroxide (NaOH) is used in industry (mainly as a chemical base) in the manufacture of paper, fabrics, detergents, food and biodiesel. Also used to clear pipes and sinks because it is corrosive. It is produced by electrolysis of an aqueous solution of sodium chloride (brine).

The handling of sodium hydroxide must be done with total care, as it presents many health risks. If ingested, it can cause serious and sometimes irreversible damage to the gastrointestinal system, and if inhaled it can cause irritation, and in high doses it can lead to death. Contact with the skin is also a dangerous fact, as it can cause a simple irritation to a severe ulcer, and in the eyes it can cause burns and corneal or conjunctive problems. In cases of contact with sodium hydroxide, the exposed region should be placed in running water for 15 min and seek medical help. If swallowed, the victim should be given water or milk without causing vomiting, if inhaled, take the victim to an open place so he can breathe. If the victim is not breathing, artificial respiration is required.

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If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

Hope this helps you

6 0
3 years ago
Answer my question please!
BaLLatris [955]

Answer:

D) 6

Explanation:

The complete balancd equation:

6Li + 1N2 = 2 Li3N

6 0
3 years ago
A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in the dissociated form
ella [17]

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂               -------->            C₄H₇O₂⁻          +           H⁺

I                    0.54x10⁻³                             0                                0

E                   0.54x10⁻³(1-x)                      0.54x10⁻³x                0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)  

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

3 0
3 years ago
Write the balanced equation for the decomposition of hydrogen peroxide to form water and oxygen.
Lerok [7]
Hydrogen peroxide is H2O2, while water is H2O and oxygen (a diatomic gas) is O2. The (unbalanced) reaction is:
H2O2 --> H2O + O2
Notice that the H2O2 has 2 H atoms, and so does H2. This means that both must have the same coefficients, and we can adjust the coefficient of O2. Since H2O2 has 2 O atoms, and H2O has 1, we multiply O2 by 1/2:
H2O2 --> H2O + (1/2)O2
This has an equivalent number of H and O atoms on either side, but we want the coefficients to be whole numbers, so we multiply everything by 2:
2H2O2 --> 2H2O + O2
7 0
3 years ago
What is the chemical formula and net ionic equations for all three solutions.
timofeeve [1]

Answer:

See answer below

Explanation:

As you are asking for chemical formula and ionic equation, then, I will assume that after the station #4 below, are the solutions you are requiring.

You are also not specifing if you want for example, result of solution 1 + solution 3. If you need that, please post that on another question.

Now for the chemical formula, you need to identify the elements in all 3 solutions, and also the type of compound.

<u>1. Solution 2 Potassium Chloride: </u>

In this case we have Potassium on one side, and Chlorine on the other side, the symbol for those are K and Cl. As Potassium have the +1 oxidation state, cause is the only one that it can have, when it's next to an halide like chlorine or bromine, it will form a binary salt. The halides, usually work with the lowest oxydation state. In the case of Chlorine it will be -1, so, the formula will be:

KCl

And the net ionic equation will be the chemical equation that shows how the charges and atoms are balanced. In this case it would be:

K⁺ + Cl⁻ ------> KCl

<u>2. Solution 1 Copper(II) sulfate: </u>

In this case we have a tertiary salt, The copper's symbol is Cu, and is working with it oxydation state +2. Sulfate is an anion and it's formula is SO₄ and works with oxydation state -2 instead.

The chemical formula and ionic equation will be:  

Copper(II) sulfate: CuSO₄

And the net equation:

Copper sulfate: Cu²⁺ + SO₄²⁻ -------> CuSO₄

<u>3. Solution 3 Sodium hydroxide:</u>

In this case, we have a compound that it's usually used in acid base reactions. This is a strong base or hydroxide, and we have the element of Sodium (Na) with the oxydation state +1, is the only one it can have, and for the other side we have the oxydrile anion OH, and together is working with the oxydation state -1. So the chemical formula will be:

NaOH

And the net ionic equation:

Na⁺ + OH⁻ -------> NaOH

Hope this helps

4 0
3 years ago
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