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boyakko [2]
3 years ago
13

Calcula la concentración porcentual de una disolución que se preparó disolviendo 30 g de Hidróxido de Litio en suficiente cantid

ad de agua para obtener 100 ml
Chemistry
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

30 % m/V o 23 % m/m

Explanation:

Al leer el problema y entender el enunciado como que se usó suficiente cantidad de agua para obtener 100 mL, con la masa de LiOH podemos determinar la concentración en m/V.

m/V es una concentración que establece la relación de gramos de soluto en 100 mL de solución.

Como los gramos de soluto son 30g, la concentración en m/V es

30/100 = 0.3 % m/V

Podemos también establecer concentración m/m la cual establece la relación como masa de soluto en 100 g de solución. Como el volumen de solución coincide con el de solvente, la masa de solución la podemos obtener sumando masa de solvente + masa de soluto

30 g + 100 g = 130 g

Si tomamos el agua como solvente puro, y por densidad (1 g/mL) la masa de agua es 100g

Así el % m/m lo calculamos como (masa de soluto/masa solucion) . 100

(30g  / 130g) . 100 = 23 % m/m

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How many moles of H2O are needed to produce 5.6 mol of NaOH?<br> Na2O + H2O --&gt; 2NaOH
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Explanation:

The balanced equation below shows that 1 mole of sodium oxide reacts with 1 mole of water to form 2 moles of sodium hydroxide respectively.

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