We have that the Concentration of solution B is 2.5 times more than solution A's concentration.
<h3>UV(Ultra violent) rays</h3>
Question Parameters:
Upon UV-analysis, Solution B gave an absorbance of 1.0
Solution A gave an absorbance of 0. 4
Generally the equation for the Absorbance is mathematically given as
A = e*c*L
Therefore
For A solution
![0.4 = e*[cA]*L](https://tex.z-dn.net/?f=0.4%20%3D%20e%2A%5BcA%5D%2AL)
For B solution
![1.0 = e*[cB]*L](https://tex.z-dn.net/?f=1.0%20%3D%20e%2A%5BcB%5D%2AL)
Hence
![\frac{0.4}{ 1} = \frac{[cA]}{ cB}](https://tex.z-dn.net/?f=%5Cfrac%7B0.4%7D%7B%201%7D%20%3D%20%5Cfrac%7B%5BcA%5D%7D%7B%20cB%7D)
[cB] = 2.5 [cA]
Therefore
Concentration of solution B is 2.5 times more than solution A's concentration.
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Answer : The volume of hydrogen gas at STP is 4550 L.
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 100.0 atm
= final pressure of gas at STP = 1 atm
= initial volume of gas = 50.0 L
= final volume of gas at STP = ?
= initial temperature of gas = 
= final temperature of gas at STP = 
Now put all the given values in the above equation, we get:


Therefore, the volume of hydrogen gas at STP is 4550 L.
I dont know if this correct, but i hope it help