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Svetradugi [14.3K]
3 years ago
7

How do unbalanced forces cause a change in speed, direction, and position of an object?

Chemistry
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

But its motion is not changing. This is because the forces acting on it from opposite sides are exactly the same size. An unbalanced force can change an object's motion. ... An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

8_murik_8 [283]3 years ago
5 0

Answer:

But its motion is not changing. This is because the forces acting on it from opposite sides are exactly the same size. An unbalanced force can change an object's motion. ... An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

Explanation:

But its motion is not changing. This is because the forces acting on it from opposite sides are exactly the same size. An unbalanced force can change an object's motion. ... An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

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A box with a mass of 3.5 kg is pushed along a table. If the net force on the box is 35 Newtons, what is the acceleration of the
Vesnalui [34]

Answer:

<h2>10 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

m is the mass

f is the force

From the question

mass = 3.5 kg

force = 35 N

We have

a =  \frac{35}{3.5}  \\  = 10

We have the final answer as

<h3>10 m/s²</h3>

Hope this helps you

8 0
3 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

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Answer:

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Explanation:

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3 years ago
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Answer:

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