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Lana71 [14]
3 years ago
9

How do cherries in a cherry tree help the plant reproduce

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
7 0
Because if the cherries are eaten them the seeds/pit will be eaten as well which will be carried by whatever ate it and pooped out and can make more of its kind but it is different with wind and water do you also want that answer?
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Write the name for CH2.
finlep [7]

Answer:

Methylene. :)

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3 years ago
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Cameron is visiting a new country while traveling around the world. He is extremely fascinated by the cuisine of this country. H
lina2011 [118]
Not exactly chemistry but ok.

Phó is one of the famous dish in Vietnamese Culture

Hence, the answer is Vietnamese Cuisine
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3 years ago
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Josie observed that when water is boiled in an open beaker it completely disappears, leaving the beaker dry. What can Josie conc
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That when water is boiled in a open beaker and it disappears that it evaporates into the air
6 0
4 years ago
A 50.0 g sample of liquid water at 25.0 degree C is mixed with 29.0 g of water at 45 degree C. The final temperature of the wate
kotegsom [21]

<u>Answer:</u> The final temperature of water is 32.3°C

<u>Explanation:</u>

When two solutions are mixed, the amount of heat released by solution 1 (liquid water) will be equal to the amount of heat absorbed by solution 2 (liquid water)

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of solution 1 (liquid water) = 50.0 g

m_2 = mass of solution 2 (liquid water) = 29.0 g

T_{final} = final temperature = ?

T_1 = initial temperature of solution 1 = 25°C  = [273 + 25] = 298 K

T_2 = initial temperature of solution 2 = 45°C  = [273 + 45] = 318 K

c = specific heat of water= 4.18 J/g.K

Putting values in equation 1, we get:

50.0\times 4.18\times (T_{final}-298)=-[29.0\times 4.18\times (T_{final}-318)]\\\\T_{final}=305.3K

Converting this into degree Celsius, we use the conversion factor:

T(K)=T(^oC)+273

305.3=T(^oC)+273\\T(^oC)=(305.3-273)=32.3^oC

Hence, the final temperature of water is 32.3°C

7 0
3 years ago
What is the concentration of a solution which is 2g in 150cm3 in g/dm3
Irina-Kira [14]

Answer:

13.33 g/dm³

Explanation:

Concentration (g/dm³)= mass(g) ÷ volume (dm³)

Now you need to convert 150 cm³ to dm³

1000cm³ = 1 dm³

thus, 150 cm3= 150 ÷ 1000

= 15dm³

and you already have mass in grams

so concentration  = 2 ÷ 0.15

= 13.33 g/dm³ and there you go.. solved ;)

8 0
3 years ago
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