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Mnenie [13.5K]
3 years ago
14

How many atoms of each element are represented in Sn(CO3)2

Chemistry
2 answers:
RideAnS [48]3 years ago
7 0
Sn=1
C=2
O=6

C gets multiplied by 2 and O3 gets multiplied by 2
Marina86 [1]3 years ago
3 0
Sn=2
C and O=6
Im pretty confident yet I forgot a bit.
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If you had 6 moles of CaCl2 and 5 moles of Na3PO4, which of these would be the limiting and excess reactant
faltersainse [42]

Answer:

Na3PO4 is excess reactant, CaCl2 is limiting reactant.

Explanation:

                                      3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl

from reaction :              3 mol        2 mol

given:                            6 mol         5 mol (X)

X = (6*2)/3 = 4 mol Na3PO4

For 6 mol CaCl2 we need 4 mol Na3PO4, but  we have 5 mol Na3PO4,

Na3PO4 is excess reactant, so CaCl2 is limiting reactant.

8 0
3 years ago
The following equation shows the correct molecules formed in the reaction, but the products are incorrect. CH4 +202=H20+ CO2 How
Hunter-Best [27]
For the equation to balance out, you would need 2 H2O on the product. That will give a total of 1 Carbon, 4 Hydrogens and 4 Oxygens on each side.
5 0
3 years ago
The lock-and-key mechanism refers to
miskamm [114]

Answer:

A). The complementary shapes of an enzyme and a substrate.

Explanation:

The Lock-and-key mechanism was proposed by Emil Fischer for the first time and characterized as the metaphor which helps in elucidating the specificity of the enzymatic reactions. In this metaphor, the lock is described as the enzyme while 'key' is characterized as the substrate which the enzyme acts upon. If the key is not appropriately sized, it will not fit into the active site i.e. the keyhole of the lock or enzyme and reaction will not take place. Thus, <u>option A</u> is the correct answer.

5 0
3 years ago
Read 2 more answers
How many grams of NaCl are in 2.0 Liters of a 3.0 M NaCl solution?
Naddik [55]

Answer:

350.64g

Explanation:

So first you must know that M is mol/L

Next solve the problem using dimensional analysis

2L NaCl (3 mol/L) = 6 mol NaCl

After you got the number of moles you should look at your periodic table to find the molar mass

I see that it's 58.44g/mol

Use dimensional analysis again!

6 mol (58.44g/mol) = 350.64g

Don't forget to make me brainliest!

4 0
3 years ago
If 4.80 mol Ca mixed with 2 mol N2, which is the limiting reactant? 3Ca (s) + N2 (g) Ca3N2 (s)
Andreyy89
Nitrogen in the limiting reactant x
4 0
2 years ago
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