All categories

3 years ago

Why is the presence of a dipole in a molecule so important?

1 answer:

5 0

The dipole moment is important in water molecules because it allows the molecule to be polar. The oxygen atom is hoarding negative charge and making the hydrogen atoms positive. This allows for the water molecules to form hydrogen bonds with other water molecules.

You might be interested in

If you expose a photosynthesizing plant to water that contains both radioactive h and radioactive o, in which of the products of

ValentinkaMS [17]

I think the answer is H in glucose and water and O in O2. Photosynthesis is the process in which green plants and other organism convert light energy to chemical energy which is used in activities within the organism. Water that is exposed to the plant reacts with carbon dioxide to produce sugar and oxygen. The radioactive O will hence show up in the oxygen molecule and the radioactive H shows up in the sugar/ glucose molecule.

3 0

3 years ago

Why does neon gas consist of individual, unbonded neon atoms while chlorine exists as diatomic chlorine molecules?

nlexa [21]

Neon gas consist of individual, unbonded neon atoms due to the stable (octet) configuration, while chlorine exists as diatomic chlorine molecules to gain stability.

<h3>How we define the stability of atoms?</h3>

Stability of any atom will be defined on the basis of the electronic configuration or the number of valence shell electrons they have.

Chlorine atom have seven electrons on the outermost shell of the atom and will able to gain 1 electron to get octet configuration, that's why present in the diatomic form.
Neon is a noble gas as they have stable configuration due to presence of 8 electrons in the valence shell, and due to stability it will not easily react with any other gas and present in single atomic form.

Hence due to stable configuration of neon it is present in the unbonded form.

To know more about octet configuration, visit the below link:

brainly.com/question/15076797

#SPJ1

6 0

2 years ago

Problem PageQuestion In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissol

Westkost [7]

I cannot help you with this question

6 0

3 years ago

When did Pangaea begin to break apart?

LUCKY_DIMON [66]

About 250 years ago ΩαΨ

7 0

3 years ago

Read 2 more answers

Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 0.98 g

cestrela7 [59]

Answer:

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

Explanation:

Mass of sulfuric acid = 0.98 g

Moles of sulfuric acid = $\frac{0.98 g}{98 g/mol}=0.010 mol$

Mass of sodium hydroxide = 0.240 g

Moles of sodium hydroxide = $\frac{0.240 g}{40 g/mol}=0.0060 mol$

$H_2SO_4(aq)+2NaOH(s)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sulfuric acid

As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.

So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.

According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sodium sulfate

Mass of 0.0030 moles of sodium sulfate :

0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

4 0

3 years ago