Answer:
Incomplete question: 9.9 mL of 0.01 M EDTA, and 10 mL of buffer with a pH of 4.
The concentration of [HY³⁻] is 1.8x10⁻²⁸mol/L
Explanation:
Given information:
10 mL of 0.01 M VOSO₄ = 0.01 L
9.9 mL of 0.01 M EDTA = 0.0099 L
10 mL of buffer = 0.01 L
pH of 4
Question: Calculate HY³⁻, [HY³⁻] = ?
Moles of EDTA:
The concentration of Y⁴⁺:
At pH = 4 Y⁴⁻ = 3.8x10⁻⁹
mol/L
The concentration of [H₂Y²⁻]:
The reaction:
H₂Y²⁻ → H⁺ + HY³⁻
The concentration of HY³⁻
Solving for HY³⁻
[HY³⁻] = 1.8x10⁻²⁸mol/L
Answer: 2, you divide the value by 1000, so... 2000/1000 = 2.
Answer:
b
Explanation:
by using formula
a=(v-u)/t
where a= acceleration
v = initial velocity = 10 m/s
u= final velocity =50 m/s
t = time taken = 2s
<span>Na + Cl = NaCl
answer : </span><span>synthesis reaction .
hope this helps!
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