How many equivalents are present in 13.5g of Al3+

1 answer:

4 0

Answer:

= 1.5 eq

Explanation:

One definition of an equivalent weight is that it is mass of a substance that gains or loses 1 mole of electrons.
Al3+ has lost 3 e-, so there are 3 equivalent weights in 1 mol Al3+.

1 mol Al3+ =3 eq. wts.
1 mol Al x(27 g / 1 mol)x(1 mol / 3 eq. wts.) = 9.0 g = 1 eq. wts.

13.5 g Al3 + x (1 eq.wt. / 9.0 g) = 1.5 eq

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