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Dovator [93]
3 years ago
9

A) Rearrange the equation to make w the subject. 2(1 + W) = P

Mathematics
1 answer:
insens350 [35]3 years ago
4 0

Answer:

Step-by-step explanation:

2(1 + W) = P\\Divide -both-sides-of-the-equation-by ; 2\\\frac{ 2(1 + W) }{2} = \frac{P}{2} \\1+ W = P/2\\W = \frac{P}{2} -1\\\\(b .)  2y = 10x + 6\\Re -write -in -slope-intercept-form : y= mx+b\\\frac{2y}{2} =\frac{10x}{2} +\frac{6}{2} \\y = 5x + 3\\Gradient = 5

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Korolek [52]

Answer:

  1. 0.80
  2. 0.289
  3. 0.20
  4. 0.711

Step-by-step explanation:

Given:

P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11

The rule of total probability states that:

P(A) = P(A\cap B) + P(A\cap B^{c})

Compute the individual probabilities as follows:

P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57

P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43

P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55

P(F^{c})=1-P(F)\\=1-0.55\\=0.45

Conditional probability of an event A given B is:

P(A|B)=\frac{P(A\cap B)}{P(B)}

  • Compute the value of P(S|F):

         P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80

  • Compute the value of P(S|F^{c})

        P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289

  • Compute the value of P(S^{c}|F)

        P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20

  • Compute the value ofP(S^{c}|F^{c})

       P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711

3 0
3 years ago
Help me maybe? Please? :))
WINSTONCH [101]

Answer:

4 1/12

Step-by-step explanation:

7/12(7)

49/12

<em>12 goes into 49 four times. 12 x 4 is 48, which leaves 1/12 left over. </em>

4 1/12

3 0
3 years ago
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