Answer:
X Y
4. 2
8. 3
12. 4
hope this is helpful for you
A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write
.
Per price increase is $20. So four price increase is $
. Hence, price per dive is 100+80=$180.
Also per price increase, 2 customers are reduced from 30. For 4 price increases,
customers are reduced. Hence, total customers is
.
So Total Revenue is:

B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.
Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.
Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as
, where a is the coefficient of
and b is the coefficient of x. So we have,

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be
. So the price that gives the greatest revenue is
.
ANSWERS:
A. $3960
B. 
C. $200
The answer is 5
Here are the steps:
First off, we will be using the distance formula of

So we have the ordered pairs of (3,1) and (6,5)
Once you plug them into the formula it should look like this:

Now we do the math inside the parenthesis and end up with:

Then you multiply by the power and simplify to get:

And the

=5
So your answer is
5
1) D
2)
3) B
4 ) F
5)C
6) F
7) D
8) C
I'm not sure about questions 4 and 7, but they may be correct.
I couldn't because I couldn't see the 2nd question
So we have the system of equations:

equation (1)

equation (2)
To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for

in equation (2):



equation (3)
Replacing equation (3) in equation (1):






equation (4)
Replacing equation (4) in equation (3):



We can conclude that the solution of our system of equations is <span>
(7/5, 21/10)</span>