She edits 3 pages in a minute, so it would take her one minute
Answer:
3/2 or 1 1/2
Step-by-step explanation:
Answer:
Mean = 78.2
Standard deviation = 5.8
Step-by-step explanation:
Mathematically z-score;
= (x-mean)/SD
From the question;
12% of test scores were above 85
Thus;
P( x > 85) = 12%
P(x > 85) = 0.12
Now let’s get the z-score that has a probability of 0.12
This can be obtained from the standard normal distribution table and it is = 1.175
Thus;
1.175 = (85 - mean)/SD
let’s call the mean a and the SD b
1.175 = (85-a)/b
1.175b = 85 - a
a = 85 - 1.175b ••••••••(i)
Secondly 8% of scores were below 70
Let’s find the z-score corresponding to this proportion;
We use the standard normal distribution table as usual;
P( x < 70) = 0.08
z-score = -1.405
Thus;
-1.405 =( 70-a)/b
-1.405b = 70-a
a = 70 + 1.405b ••••••(ii)
Equate the two a
70 + 1.405b = 85 - 1.175b
85 -70 = 1.405b + 1.175b
15 = 2.58b
b = 15/2.58
b = 5.81
a = 70 + 1.405b
a = 70 + 1.405(5.81)
a = 78.16
So mean = 78.2 and Standard deviation is 5.8
Answer:
The same number of tickets was sold on the fourth day and tenth day.
Step-by-step explanation:
Given, T(d) is a function that relates the number of tickets sold for a movie to the number of days since the movie was released.
The average rate of change in a function with respect to the independent variable gives the value of change in a particular period.
If average rate of change in T(d) for the interval d = 4 and d = 10 is is 0 , that means nothing has been changed in the number of tickets sold on 4th day and 10th day after the film release.
Hence, the correct statement is "The same number of tickets was sold on the fourth day and tenth day."
The answer is A
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