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mario62 [17]
3 years ago
8

Y=-3x^2-30x-27 find the zeroes of the function by rewriting the function in intercept form

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0
<span>y=-3x²-30x-27

Δ=b²-4ac=(-30)²-4.(-3).(-27)=900-324=576 ∴ √Δ=24

x'=(-b+√Δ)/2a=(-(-30)+24)/2.(-3)=-54/6=-9

x''=</span><span>(-b-√Δ)/2a=(-(-30)-24)/2.(-3)=-6/6=-1

Raízes são x''=-9 e x''=-1
</span>
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MAXImum [283]

I think the answer is option 3.

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3 years ago
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Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply. 1.The slope of one boundary line i
zloy xaker [14]

Answer:

2.Both boundary lines are solid.

3.A solution to the system is (1, 3)

5.The boundary lines intersect.

Step-by-step explanation:

we have

y\leq 3x+1 ----> inequality A

The solution of the inequality A is the shaded area below the solid line y=3x+1

The slope of the solid line is 3

The point (1,3) is  a solution of inequality A (lie in the shaded area of the solution set)

y\geq -x+2 ----> inequality B

The solution of the inequality B is the shaded area above the solid line y=-x+2

The slope of the solid line is -1

The point (1,3) is a solution of inequality B (lie in the shaded area of the solution set)

The solution of the system of inequalities is the shaded area between the two solids lines

see the attached figure

<u><em>Verify each statement</em></u>

1.The slope of one boundary line is 2

The statement is False

2.Both boundary lines are solid.

The statement is True

3.A solution to the system is (1, 3)

The statement is True

4.Both inequalities are shaded below the boundary lines

The statement is False

5.The boundary lines intersect.

The statement is True

The intersection point is (0.25,1.75)

see the attached figure

7 0
3 years ago
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Plz, help brainliest look at the picture PLZ HELP!!!
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Answer:

i think its B

Step-by-step explanation:

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The speed of a sparrow is x km/h in still air. When the
Semmy [17]

Answer:

x = 5m/s

Step-by-step explanation:

Distance flying out = 12 km  (headwind)

Distance flying back = 12 km (tailwind)

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speed going out (with headwind) = (x - 1) km/h

speed coming back (with tailwind) = (x + 1) km/h

Time taken to go out = distance going out / speed going out

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Time taken to come back = distance coming back / speed coming back

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5 =[ 12/(x-1) ] + [ 12/(x-1)]

expanding this, we will get

5x² - 24x - 5 = 0

solving quadratic equation, we will get

x = -1/5 (impossible because speed cannot be negative)

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x = 5 (answer)

4 0
3 years ago
How many seconds equal 3.6 hours?
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