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Alinara [238K]
3 years ago
7

Help?????...........

Mathematics
1 answer:
AlekseyPX3 years ago
4 0
i believe it's 25.2. because if you do 3.6x7= 25.2
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Write an equation y is 20% what is x
lisabon 2012 [21]

Answer:

x + .20 = 1

Step-by-step explanation:

The equation would be x + .20= 1, or 1.00, because if you turn 20% into a decimal, it becomes .20. The total you are trying to find is 1 whole, in which this case it would simply be one as there is no other information. The x is first as if you had the .20 first, you would have to divide each side by .20, which would make x = 5, and that would not make sense.

Finding X: To find, subtract on each side by .20 due to the fact you are adding and need to do the opposite, .20-.20 cancels out and 1.00-.20 is .80, so you are left with x=.80

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For 3/4 (three fourths) of a pound of peanuts, Jimmy paid $2.25. What is
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Max correctly solved this inequality.
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2 years ago
3-5(3a+6) in standard form
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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%283x%20%2B%204%29%20%20-%207%20log_%7B4%7D%7Bx%7D%5E%7B2%7D%20%20%2B%20%20log_%
olga2289 [7]

First of all, we need all logarithms to have the same base. So, we use the formula

\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}

To change the second term as follows:

\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}

Finally, using the property

\log(a^b)=b\log(a)

we have

\dfrac{\log_2(x^2)}{2}=\log_2(x)

So, the equation becomes

\log_2(3x+4)-7\log_2(x)+\log_2(x)=2 \iff \log_2(3x+4)-6\log_2(x)=2

We can now use the formula

\log(a)-\log(b)=\log\left(\dfrac{a}{b}\right)

to write the equation as

\log_2(3x+4)-6\log_2(x)=2 \iff \log_2(3x+4)-\log_2(x^6)=2 \iff \log_2\left(\dfrac{3x+4}{x^6}\right)=2

Now consider both sides as exponents of 2:

\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

5 0
3 years ago
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