Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The weight of the bucket is 
The depth of the well is 
The weight of the water is 
The rate at which the bucket with water is pulled is 
The rate of the leak is 
Generally the workdone is mathematically represented as
]
Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as
Here I is the rate of water loss in lb/ft mathematically represented as
=> 
=> 
So
=> 
So
]
=> ![W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.](https://tex.z-dn.net/?f=W%20%3D%20%20%5B47x%20-%20%5Cfrac%7B0.1x%5E2%7D%7B2%7D%20%5D%7C%5Cleft%2060%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
=> ![W= [47(60) - 0.05(60)^2]](https://tex.z-dn.net/?f=W%3D%20%5B47%2860%29%20-%200.05%2860%29%5E2%5D)
=>
Answer:
The answer is B. 1
Step-by-step explanation:
rise over run
1/1=1
2+4z-18
change it so it's an equation
2+4z-18=0
then get 4z alone on one side by subtracting 4z from both sides
2-18=-4z
-16= -4z
divide both sides by -4
a negative divided by a negative becomes positive
4 =z
plug it in
2+4(4)-18
4x4 is 16
2+16-18=0
0=0
the same can be done for the second one 2+k-8
make it 2+k-8=0
move the k to get it alone so subtract k from both sides
2-8=-1k
-6 = -1K
you can divide by K to make K=6
plug in 2+6-8=0
0=0
Running laps and timing them
Answer: B. 84 in²
Step-by-step explanation:
Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).
Find the area of the rectangle:
Area of a rectangle=length*width
Area of rectangle=(5 in)( 10 in)
Area of rectangle=50 in²
Next, calculate the area of the trapezoid:
Area of trapezoid=
h=10 in-6 in
h=4 in
Area of trapezoid=
Area of trapezoid=
Area of trapezoid=
Area of trapezoid=
Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²
