A. logic, would be your answer i believe!
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
Answer:
.y₂ = 0.5704 m
, y2= 44.47 m,
Explanation:,
For this exercise we will use the kinematics relations
Ball
y₁ = y₀ + v₀₁ t
y₀ = 11.0 m
v₀₁ = 5.10 m / s
Pellet
y₂ = 0 + v₀₂ t - ½ g t²
V₀₂ = 39.0 m / s
At the meeting point the two bodies have the same height
y₁ = y₂
y₀ + v₀₁ t = v₀₂ t -1/2 g t²
11 + 5.1 t = 39 t - ½ 9.8 t²
4.9 t² - 33.9 t +11 = 0
.t2 - 6,918 + 2,245 = 0
t = [6,918 ±√ 6,918 2 - 4 2,245)] / 2
t = [6,918 ± 6.2356.] / 2
t₁ = 6.58 s
t₂ = 0.3412 s
Let's calculate the positions for each time
t₂ = 0.3412 s
y₂ = 39 t - ½ 9.8 t2
y₂ = 39 0.3112 - ½ 9.8 0.3412²
y₂ = 0.5704 m
.t1 = 6.58 s
.₂ = 39 6.58 - ½ 9.8 6.58 ^ 2
y2= 44.47 m
Answer:
The correct answer is C NERVOS SYSTEM as it allow ALLL the sense to work
Explanation:
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
Answer:
1.1 m
Explanation:
PE = mgh
6.7 J = (0.62 kg) (9.8 m/s²) h
h = 1.1 m