William Parsons was the first astronomer to show that spiral nebulae have large Doppler shifts.
<h3>What are Spiral nebulae?</h3>
- In space, a nebula is a huge cloud of gas and dust. Some nebulae, including multiple nebulae, are made of gas and dust that have been released from the explosion of a dead star called a supernova. There are other nebulae that are star-forming regions.
- Edwin Hubble began observing Cepheid variables in many spiral nebulae, including the alleged Andromeda Nebula, in 1923, demonstrating that they are, in fact, full-fledged galaxies outside our own. Since then, the phrase spiral nebula has lost favor.
- One group of astronomers believed that spiral nebulae were parts of our Milky Way galaxy, whereas the other group believed that these objects were actual galaxies that were outside of the Milky Way galaxy.
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Light intensity and distance is
interrelated. When the distance changes, the intensity of light changes. This relationship
is called inverse-square relationship. The inverse-square relationship refers
to the fact that when distance changes, light intensity also changes: inverse
because when distance decreases, light density increases and when distance
increases, the latter decreases; square refers to the fact that light intensity
and distance is not a one-to-one relationship.
Yes it would be the same your weight would change:)
Answer:
260 km/h
Explanation:
Motion is said to be relative when the motion observed by the observer depends on the location (frame) of the observer.
When two objects are moving in opposite directions, the relative motion is obtained by subtraction.
Hence the plane is moving at (285 - 25) km/h giving 260 km/h
Answer:
r=6.05km/hr
z=59.1 degree to the horizontal
Explanation:
A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place
can be solved using pythagoras theorem
r^2=o^2+a^2
r^2=5.2^2+3.1^2
r^2=36.65
r=6.1km/hr is te birds velocity relative to the ground
tanz=5.2/3.1
z=tan^-1(5,2/3.1)
z=59.1 degree to the horizontal
