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Vadim26 [7]
2 years ago
8

Sometimes, supplies can be delivered to people in remote areas by dropping them off from a plane. This is usually the case for g

round troops working in areas where planes are unable to land safely. Parachutes are attached to boxes to prevent damage to items when they land. Compare the parachute setups in the image; A has three parachutes attached, B has one parachute attached, and C has two parachutes attached. If every parachute in all three setups are the same size, and each setup was attached to a 50-pound box, which lists the order the boxes would land from slowest to quickest?
A) A, B, C
B) B, C, A
C) А,С, В
D) В, А, С​
Physics
1 answer:
FrozenT [24]2 years ago
8 0

The order the boxes would land from slowest to quickest is A,C,B which is option C.

<h3>What is a Parachute?</h3>

This is a device used to slow the motion of an object through an atmosphere by creating drag.

The size of the parachute affects the speed of falling because a larger parachute allows it to displace more air, causing it to fall more slowly. The one with three parachutes which is A will fall slowest and the one with just one will fall fastest.

Read more about Parachutes here brainly.com/question/499768

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A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0
3 years ago
food does not pass through the liver or the pancreas why are these organs dtill important parts of the digestive system?
kirill115 [55]

Your pancreas makes a digestive juice that has enzymes that break down carbohydrates, fats, and proteins. The pancreas delivers the digestive juice to the small intestine through small tubes called ducts. Liver. Your liver makes a digestive juice called bile that helps digest fats and some vitamins.

5 0
2 years ago
A nonprofit organization posted an article in the local newspaper about a recent marathon. The marathon raised money for vaccina
mr Goodwill [35]

Answer:

An original funding source.

Explanation:

Non profit organization planned a marathon through which the money was raised for the vaccinations help, hence; here they are showing the original funding source, that is the number of runners and the amount raised by them.

3 0
4 years ago
Read 2 more answers
Long Jump: inital center of mass height of 1.08 m, final center of mass height of 0.42 m, projection velocity of 8.7 m/s, projec
sammy [17]

Answer:

1) The maximum jump height is reached at A. 0.337s

2) The maximum center of mass height off of the ground is B. 1.64m

3) The time of flight is C. 0.834s

4) The distance of jump is B. 7.49m

Explanation:

First of all we need to decompose velocity in its rectangular components, so

v_{xi}=8.7m/s(cos 22.3\°)=8.05m/s= constant\\v_{yi}=8.7m/s(sin 22.3\°)=3.3m/s

1) We use, v_{fy}=v_{iy}-gt, as we clear it for t and using the fact that v_{fy}=0 at max height, we obtain t=\frac{v_{iy}}{g} =\frac{3.3m/s}{9,8m/s^{2}} =0.337s

2) We can use the formula y_{max}=y_{i}+v_{iy}t-\frac{gt^{2}}{2} for t=0.337s, so

y_{max}=1.08m+(3.3m/s)(0.337s)-\frac{(9.8m/s^{2})(0.337)^{2}}{2}=1.64m

3) We can use the formula y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find total time of fligth, so 0.42=1.08+3.3t-\frac{(9.8)t^{2}}{2}\\0=-4.9t^{2}+3.3t+0.66, as it is a second-grade polynomial, we find that its positive root is t=0.834s

4) Finally, we use x=v_{x}t=8.05m/s(0.834s)=6.71m, as it has an additional displacement of 0.77m due the leg extension we obtain,

x=6.71m+0.77m=7.48m, aprox x=7.49m

5 0
4 years ago
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Dovator [93]
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
3 years ago
Read 2 more answers
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