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Vadim26 [7]
1 year ago
8

Sometimes, supplies can be delivered to people in remote areas by dropping them off from a plane. This is usually the case for g

round troops working in areas where planes are unable to land safely. Parachutes are attached to boxes to prevent damage to items when they land. Compare the parachute setups in the image; A has three parachutes attached, B has one parachute attached, and C has two parachutes attached. If every parachute in all three setups are the same size, and each setup was attached to a 50-pound box, which lists the order the boxes would land from slowest to quickest?
A) A, B, C
B) B, C, A
C) А,С, В
D) В, А, С​
Physics
1 answer:
FrozenT [24]1 year ago
8 0

The order the boxes would land from slowest to quickest is A,C,B which is option C.

<h3>What is a Parachute?</h3>

This is a device used to slow the motion of an object through an atmosphere by creating drag.

The size of the parachute affects the speed of falling because a larger parachute allows it to displace more air, causing it to fall more slowly. The one with three parachutes which is A will fall slowest and the one with just one will fall fastest.

Read more about Parachutes here brainly.com/question/499768

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Clouds in our atmosphere cause us to see the different phases of the moon.
krok68 [10]

Answer:

False

Explanation:

:)

8 0
3 years ago
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Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
deff fn [24]

Answer:

\theta_2 - \theta_1 = 156.93 degree

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

y = A sin\omega t

y = \frac{A}{5}

so now we have

\frac{A}{5} = A sin\omega t

now we have

\theta_1 = 11.53 degree

so the phase other particle in opposite direction is given as

\theta_2 = 180 - 11.53 = 168.46 degree

so we have phase difference given as

\theta_2 - \theta_1 = 168.46 - 11.53

\theta_2 - \theta_1 = 156.93 degree

7 0
3 years ago
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

3 0
3 years ago
The sense of equilibrium responds to movements of the head. It is divided into two types--static and dynamic equilibrium. Descri
Sonja [21]

Answer:

nodding of head ,yes- static equilibrium

nodding of head, no- dynamic equilibrium.

Explanation:

static equilibrium monitors head position when body is not moving .

dynamic equilibrium monitors the angular or rotational movements of the head when body moves.

5 0
2 years ago
Read 2 more answers
Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation
vazorg [7]

The electrical force between these two charges remains the same. In coulomb’s law, it states that the magnitude of two charges (product of two charges) is inversely proportional to the square of the distance. Since both the magnitude and the distance are halved, therefore, the change in both quantities will have no effect in the value of electrical force.

6 0
2 years ago
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