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3 years ago

Identify the balanced single displacement reaction.

Chemistry

2 answers:

Luda [366]3 years ago

8 0

Answer: $CuCl_2+Fe\rightarrow Cu +FeCI_2$

Explanation:

This is a single replacement reaction in which iron replaces copper from its salt solution. As iron is more reactive than copper , it easily loses electrons to convert to $Fe^{2+}$ in $FeCl_2$ and $Cu^{2+}$ in $CuCl_2$ accepts electrons to form $Cu$ .

The equation is also balanced as equal number of atoms of each element are present on reactant and product side.

1. $CuCl_2+Fe\rightarrow 2Cu +FeCI_2$ : The equation is not balanced.

2. $PbCl_4+2Ca(OH)_2\rightarrow 2CaCl_2+Pb(OH)_4$ : This is a double displacement reaction and is balanced.

4. $PbCl_4+2Ca(OH)_2\rightarrow 2CaCl_2+4Pb(OH)_4$ : This is a double displacement reaction and is not balanced.

tekilochka [14]3 years ago

3 0

CuCl2<span> + Fe ⟶ Cu + FeCI</span><span>2</span>

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When the ph of an aqueous solution is changed from 1 to 2, the concentration of hydronium ions in the solution is.

kiruha [24]

Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

if pH=1,H=10−1=0.1M
if pH=2,H=10−2=0.01M

Therefore, 0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

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2 years ago

Compute 9.3456+2140.56. Round the answer appropriately.

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3 years ago

Use your understanding of the ideal gas law to

PolarNik [594]

Answer:The ideal gas law is represented mathematically as: PV=nRT. P- pressure, V- volume, n-number of moles of gas, R- ideal gas constant, T- temperature.

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he ideal gas law has so many limitations.

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3 years ago

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3 years ago

Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH

uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

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3 years ago