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3 years ago

What happens to the influenza virus every 20-40 years, and why? What are the recent example(s)?

Chemistry

1 answer:

LenKa [72]3 years ago

8 0

Answer:

The influenza virus is mutated every 20-40 years.

Explanation:

Large mutations occur every 20-40 years. This results in a new influenza virus to which the human population has no protection. These large mutations are almost always followed by an influenza pandemic.

Hope this helps!

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Solution A has a concentration of 3 M. If solution B is 5 times more concentrated than A what is it’s concentration?

raketka [301]

The answer is 15 M!!

5 0

2 years ago

What is the electron configuration of the element in period 2 that has 5 valence electrons (valence electrons are the electrons

balu736 [363]

Answer:

Nitrogen

Explanation:

N= is the symbol

electronic configuration

1s2 2s2 2p3

8 0

2 years ago

1 3.1.2

Pachacha [2.7K]

Answer: (Kr) 5s2

Explanation:

Apex

7 0

2 years ago

Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100

mash [69]

Answer:

10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate

So,

8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate

Solving for X,

X = (8.25 g × 116.16 g) ÷ 88.11 g

X = 10.87 g of Ethyl Butyrate

8 0

3 years ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0

2 years ago