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nordsb [41]
2 years ago
5

When the ph of an aqueous solution is changed from 1 to 2, the concentration of hydronium ions in the solution is.

Chemistry
1 answer:
kiruha [24]2 years ago
7 0

Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

  • if pH=1,H=10−1=0.1M
  • if pH=2,H=10−2=0.01M

Therefore,  0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

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H3PO4 + Ca(OH)2 → Ca(H2PO4)2 + H2O
aniked [119]

Given question is incomplete. The complete question is as follows.

Balance the following equation:

H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Answer: The balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

Explanation:

When a chemical equation contains same number of atoms on both reactant and product side then this equation is known as balanced equation.

For example, H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Number of atoms on reactant side:

H = 5

P = 1

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Number of atoms on product side:

H = 6

P = 2

O = 9

Ca = 1

In order to balance this equation, we will multiply H_3PO_4 by 2 on reactant side and we will multiply H_2O by 2 on product side. Hence, the balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

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When the reaction mixture is worked-up, it is first washed three times with 5% sodium bicarbonate, and then with a saturated nac
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Solution:

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