All categories

4 years ago

The width of a rectangle is 14 less than twice the length. The perimeter is 32cm. What is the area of the rectangle?

Mathematics

1 answer:

Alex_Xolod [135]4 years ago

7 0

To find a perimeter of a rectangle, add all of the sides together

To find the area of a rectangle, multiply length times width.

I attached a photo of all of the work and answers.

Hope this helps.

You might be interested in

Which function has the same domain as y=2 square root x

matrenka [14]

We are given the function
y = 2 √x

We are asked for the function that has the same domain as the given function

First, the domain for the given function is this
{ x | x ≥ 0 }

So, any function that has a domain of x that is equal to or greater than 0. Some examples:
f(x) = √x - 2
f(x) = 5 √x

4 0

4 years ago

Read 2 more answers

Help me pls its hard for me atleast

QveST [7]

Answer:

the awnser is 12 because you have to divide

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

When number can each term of the equation be multiplied by to eliminate the fractions before solving 6-3/4x+1/3=1/2x+5

PolarNik [594]

Answer:

Step-by-step explanation:

You need to find the least common denominator (LCD) to all the denominators of the fractions present in the equation. These denominators are (writing them in their prime factor form to make our calculations easier):

$4=2^2\\3=3\\2=2$

Therefore, we need to include a factor of 3, and two factors of 2 ( $2^2$ ) in our least common denominator, so this LCD will be a perfectly divided by all three given denominators, therefore eliminating all fractions in the equation.

Our LCD is = $3*2^2=13*4=12$

6 0

3 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$

4 0

3 years ago

What is suface area of a cone with 16in radius and 38in hight?

tresset_1 [31]

2876.74665 in

After the in you got to put a number 2 above it I don't know how to make the symbol.

7 0

3 years ago