All categories

3 years ago

And here's the third one.

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Yes her number line make sense in why is because the way she sat it up was the right way..

You might be interested in

How is everyone's day

weqwewe [10]

Answer:

Mine's going good. Just doing school at home and playing volleyball

8 0

2 years ago

Adam has been asked to post a parcel for a family member. He has been told that the parcel weighs 12 lbs 8 oz. 1lb = 16 oz 1lb =

jasenka [17]

Answer:

The weight of the parcel is approximately 6 kilograms.

Step-by-step explanation:

The weight of the parcel is 12 lbs and 8 oz.

1 lb = 16 oz

So, 8 oz = $\frac{1}{2}lb = 0.5$ lb.

That means, 12 lbs and 8 oz = (12 + 0.5) lbs = 12.5 lbs

Now, 1 lb = 454 g

So, 12.5 lbs = (12.5 × 454) g = 5675 g

As, 1 kilogram = 1000 g

That means, 1 g = 0.001 kilogram

So, 5675 g $= (5675 \times0.001) kilograms= 5.675 \approx 6$ kilograms. (Rounded to the nearest whole kilogram)

Thus, the weight of the parcel is approximately 6 kilograms.

5 0

3 years ago

Myra saved $15 a month for 18 months. She bought a book for $46.50 and a tennis racquet for $129.95. How much does she have left

Elis [28]

Answer:

Step-by-step explanation:

15*18=270.

270-46.50=223.5

223.5-129.95=93.55.

A. $93.55

7 0

2 years ago

? points Simplify completely : 5x - 20 9x - 36

pantera1 [17]

Answer:

5/9

Step-by-step explanation:

4 0

2 years ago

The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consume

AfilCa [17]

Answer:

Yes. The male and female consumers differ in the amounts they spend.

Step-by-step explanation:

We can express the null and alternative hypothesis as:

$H_0: \mu_m=\mu_w\\\\H_1: \mu_m\neq\mu_w$

It is assumed a significance level of 0.05.

The standard deviation of the difference of means is calculated as:

$s=\sqrt{\frac{s_m^2}{n_m} +\frac{s_w^2}{n_w} } =\sqrt{\frac{35^2}{40} +\frac{20^2}{30} } =\sqrt{30.625+13.333} =\sqrt{43.958} =6.63$

The test statistic is

$t=\frac{(M_m-M_w)-0}{s}=\frac{135.67-68.64}{6.63}=10.11$

The degrees of freedom are:

$df=n_1+n_2-2=40+30-2=68$

The P-value for t=10.11 is P=0, so it is smaller than the significance level. The null hypothesis is rejected.

We can conclude that male and female consumers differ in the amounts they spend.

5 0

3 years ago