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bazaltina [42]
3 years ago
8

How to graph 3y=-x-3

Mathematics
1 answer:
saw5 [17]3 years ago
3 0
So you’ll have to isolate the y by dividing the other side of the equation by 3

3y=-x-3
y=-1/3x-1

-1 will be your y intercept and the slope will be -1/3

you’ll start your line by plotting (0,-1)
then from that point you’ll count down one, right 3
or up one, left 3

hope this helps (:
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Which pair of adjacent angles is complementary?
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2 years ago
Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])
Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

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cos(θ + φ) = -96/125 - 21/125

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8 0
2 years ago
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3 0
3 years ago
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Answer:

Step-by-step explanation:

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Answer:

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Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

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4 years ago
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