Let
be a probability that i-th light fails, where i=1,2,3. Then,
is the probability that i-th light remain bright.
<span>If the lights fail independently of each other, the probability that a string of lights will remain bright for two years is:
</span>
.
Mathematically, that is 12(8+t). Distribute the 12, and you get 96 + 12t, or 12t + 96.
Answer:
a = 3, -3
Step-by-step explanation:
Multiply (a+3)/(a+3) to 2/(a-3) and multiply (a-3)/(a-3) to 2/(a+3) to get:
2(a+3)/(a-3) and 2(a-3)/(a+3) which equals (2a+6)/(a^2-9) and (2a-6)/(a^2-9)
add those two together to get (4a)/(a^2-9) which is equal to a/(a^2-9) on the other side. Cross multiply to get 4a^3 - 36a = a^3 - 9a, add/subtract like terms and you get a = 3 or -3
Answer:
- The minimum height is 154 cm
- The first quartile Q1 is 168.8 cm
- The second quartile Q2 (or the median) is 171.9 cm
- the maximum height is 193 cm
Step-by-step explanation:
Box plot allows to identify minimum point, maximum point, Q1, Q3 and the median.
See the below (attached) image for the locations of the minimum point, maximum point, Q1, Q3 and the median.
