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Murljashka [212]
3 years ago
8

5x + 11 - 8x - 14 Can someone show me how I would do this equation please?

Mathematics
2 answers:
8090 [49]3 years ago
6 0

Answer:

if the above equation is equal to 0 then value of x=-1

larisa [96]3 years ago
3 0

Answer:

5x + 11 - 8x - 14 = -3x -3

Step-by-step explanation:

5x + 11 - 8x - 14

5x - 8x + 11 - 14

-3x -3

5x + 11 - 8x - 14 = -3x -3

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Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x –
mafiozo [28]

Answer:

0 = x2 - 9x + 20

Step-by-step explanation:

y + 5x = x² + 10     Simplify this equation

  - 5x   - 5x

y = x² - 5x + 10

Set both equations equal to each other since they both equal y

x² - 5x + 10 = 4x - 10

    -4x           - 4x

x² - 9x + 10 = -10

         + 10   + 10

x² - 9x + 20 = 0

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4 years ago
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Angelina_Jolie [31]

The answer is

6 hours : 1 book

6 0
3 years ago
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A culture started with 5,000 bacteria. After 4
Tresset [83]

Answer: After 13 (12) hours, there would be 6,500 bacteria across the culture.

Step-by-step explanation:

The bacteria grew by 500 each 4 hours, so to know how much there would be 13 hours later:

Simple, add 500 bacteria to every 4 hours until you reach 13 hours. 4 = 5.5k, 8 = 6k, 12 = 6.5k. Now, 12 is closer to 13 than anything we would've gotten if we kept going.

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7 0
3 years ago
The diagram shows a triangle.The sizes of the angles, in degrees, arex 30Work out the value ofx.Diagram NOTaccurately drawn
Korvikt [17]
X=25 degrees

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4 0
3 years ago
The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp
Dafna1 [17]

Solution:

Given:

V=16300(0.94)^t

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}

Hence,

\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\  \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\  \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0
1 year ago
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