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Sphinxa [80]
1 year ago
12

Help me wit my math please

Mathematics
1 answer:
White raven [17]1 year ago
7 0

we have the expression

3x+2y

Verify for each ordered pair

so

a) (0,6)

substitute

3(0)+2(6)=12

b) (3,2)

3(3)+2(2)=13

c) (4,1)

3(4)+2(1)=14

d) (5,-2)

3(5)+2(-2)=11

therefore

maximum value for option C

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Factor 2x2 + 7x + 3. <br> (2x + 2)(x + 1) <br> (2x + 3)(x + 1) (2x + 1)(x + 3)
maks197457 [2]
<h3>Answer:</h3>

(2x + 1)(x + 3)

<h3>Step-by-step explanation:</h3>

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

_____

<em>Constructed solution</em>

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

Now, rewrite the x term using the sum of these numbers.

... 2x² +(1 +6)x +3

... 2x +x +6x +3 . . . . eliminate parentheses

... (2x +x) +(6x +3) . . . . group pairs of terms

... x(2x +1) +3(2x +1) . . . . factor each pair

... (x +3)(2x +1) . . . . . . matches the last selection

6 0
3 years ago
Find the exact value of each trigonometric function for the given angle θ.
Kay [80]

Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

8 0
3 years ago
What is the area of the shaded region? use 3.14 for pi
Alina [70]

Answer:

13.8

Step-by-step explanation:

Area of square = πr²

=22/7 × 4²

=50.2

Area of square = l²

=8²

= 64

Area of shape is 64 - 50.2 = 13.8

7 0
3 years ago
Read 2 more answers
1. Now consider equations of the form , where a, b, and c are all positive integers and . (a) Create an equation of this form th
tino4ka555 [31]

a) To create an equation

X+X =7

so what's X over here is

7² = x²

X=3.5

b) Real numbers are mixture of irrational and rational numbers so √5 and √6 are irrational where as 5 and 6 are not but they two are equal to each other.

Explaining the equation:

√5 +√6 = √11

5 +6 = 11

√11 =11

√= 11 ÷ 11

√= 1

So if root is 1 then -1 is -√

this is the answer propably

4 0
3 years ago
Length in the right triangle 7cm 10cm
horsena [70]
I think it would be 70 cm
5 0
4 years ago
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