A (0,0), B(8,10), C(5,-10) First, find the slope of AB and AC, slope of AB is 5/4, slope of AC is -2 next, find the negative reciprocals of the slopes: -4/5 and 1/2 respectively so the altitude of AB is a line with a slope of -4/5 passing through (5,-10) the altitude of AC is a line with a slope of 1/2 passing through (8,10) find these two lines: Plug (5,-10) in y=(-4/5)x+b to find b, b=-6, so y=(-4/5)x -6 plug (8,10) in y=(1/2)x +b to find b, b=6, so y=(1/2) x +6
the point where these two lines meet is the orthocenter. y=(-4/5)x -6 y=(1/2) x +6 (-4/5)x -6=(1/2) x +6 x=-120/13 y=(1/2)*(-120/13)+6=18/13 so the orthocenter is (-120/13, 18/13) these numbers look odd, but I've run the vertex through an orthodox calculator, and got the same result.
