Solve the system of equations.<br> -9 - 6y = 15<br> 9x

HELPPPPPPPPPPPPPPP RATE 5 STARSS

Stels [109]

Answer:

13. c,

14. a.

Step-by-step explanation:

13. The length of a side PQ with coordinates of

P as (x,y) and Q as (w,z)

is: $\sqrt{(x-w)^{2} +(y-z)^{2} }$

so, the length of the side AB =

$\sqrt{(5-5)^{2}+(-2+7)^{2} } =\sqrt{0^{2}+5^{2} } =5$

the length of side BC =

$\sqrt{(5-1)^{2}+(-7+2)^{2} } =\sqrt{(4)^{2}+(-5)^{2} } =\sqrt{4^{2}+5^{2} }$

the length of side AC=

$\sqrt{(5-1)^{2} +(-2+2)^{2} } =\sqrt{4^{2} } =4$

now, the easiest one will be when the vertices are on the coordinate axes.

so, option c will be the most appropriate one.

14. If u see the figure clearly, the lines l and FH are parallel.

the parallel postulate, i.e, the alternate interior angles will always be congruent.

here, the alternate interior angles are angle1 and angle4.

therefore to prove this step, he used parallel postulate as a reason.

so, the correct option is "a"

7 0

4 years ago

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

vovikov84 [41]

9514 1404 393

Answer:

y = 7

Step-by-step explanation:

The slope is ...

m = (7 -7)/(0 -4) = 0

The y-intercept is the point (0, 7), so the slope-intercept equation is ...

y = mx +b

y = 0·x +7

Simplifying this puts it in standard form:

y = 7

8 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Question 33 with explanation please! 15 points

Dominik [7]

1. do you realize you have Paul at the bottom of the paper, 2. Well, Its Paul, because it says “all the girls only have 1 pet and 1 brother or sibling,”

7 0

3 years ago

Read 2 more answers

Can someone please help me it’s urgent

Evgen [1.6K]

Answer:

8.5 in

Step-by-step explanation:

You are solving for the hypotenuse right? So you would use this formula:

c = square root a^2+b^2

the c is the hypotenuse (long side of a right triangle) and a will be 4 and b will be 7.5. substitute the numbers in, solve, and you get 8.5 inches!

x = square root 4^2 + 7.5^2

x = square root 16 + 56.25

x = square root 72.25

x = 8.5 inches

8 0

3 years ago

Solve the system of equations. -9 - 6y = 15 9x – 10y = 145