The volume of a pyramid is V = 1/3 x base length^2 x height
Let X = base length.
We are told the height is 1/2 the length, so height would be 1/2x
Now we have:
972 = 1/3 * x^2 * 1/2x
Simplifying we get:
972 = 1/6x^3
Multiply both sides by 6:
5832 = x^3
Take the cube root of both sides:
x = 18
The length of the base is 18 inches.
The height is 1/2 that, so the height would be 18/2 = 9 inches.
The second one !!!
I’m pretty sure
Do this.
38 divided by two
then use the equation
38=5+2x
(a) the given triangle is a isosceles triangle, therefore the two leg sides will be congruent, as well as the two base angles. It is given that one of the base angles ∠XYW is 70°, therefore, due to the law of a isosceles triangle, the measurement of ∠XWY is also 70°. Remember, a triangle's interior angles add up to 180°, so:
180 - (70 + 70) = 180 - 140 = 40
40° is your answer.
m∠X = 40°
(b) All sides are congruent, making it a equilateral triangle. If it is a equilateral triangle, then all the angles also have the same measurement. The total of the interior angle's measurement is 180°. Divide by the amount of angles, 3:
180/3 = 60
60° is your answer.
m∠V = 60°
~
