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Cerrena [4.2K]
3 years ago
14

Find an equation in slope-intercept form for the perpendicular bisector of the segment with endpoints H(–3, 2) and K(7, –5).

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0
Y=7/10x+(-4)
The slope of HK is -10/7, so a perpendicular slope is 7/10
The y intercept of a line with m=7/10 going through the midpoint of HK has a y intercept of -4, therefore: y=7/10x+(-4)
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Find x if Q is the midpoint of PR, PQ-19, and PR 8x + 14<br>a. 14. B7<br>C 3. D5​
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Answer:

Step-by-step explanation:

If Q is the midpoint of PR and PQ is 19, that means that QR is also 19 and the total length of PR is 38. Therefore,

PQ + QR = PR and

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3 years ago
Triangle ABC is described below. Find all possible values for B, C, and c.
aliya0001 [1]

Answer:

c = 27.9

B = 62.13°

C = 89.90°

Step-by-step explanation:

We are given the following values:

A= 121.59°, a = 27.9 cm, b = 52.6 cm

a) Finding side c

We would use Pythagoras Theorem

c² = a² + b²

c = √(a² + b²)

c = √(27.9² + 52.6²)

c = 59.54cm

≈ Approximately = 59.5cm

b) Finding B

We would be using Cosine rule to find Angle B

Cos B = a² + b² - c²/2ab

B = arc cos ( a² + c² - b²/2ac)

B = arc cos( 27.9² + 59.5² - 52.6²/ 2 × 27.9 × 59.5)

B = 62.13268°

B = 62.13°

c) Finding C

We would be using Cosine rule to find Angle C

Cos C = a² + b² - c²/2ab

C = arc cos ( a² + b² - c²/2ab)

C = arc cos( 27.9² + 52.6² - 59.5²/ 2 × 27.9 × 52.6)

C = 89.9°

4 0
4 years ago
Find the 12th term of the geometric sequence 2, -10, 50, ...
Evgen [1.6K]
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4 years ago
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